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+//calculating deltaG and Kc
+//Example 6.9
+clc
+clear
+Ecell=0.89//in V
+n=6
+F=96500// in 1/mol
+deltaG=-n*F*Ecell//in C.V or J
+//Kc related to deltaG
+R=8.314//in J/molk
+T=298//in K
+Kc1=10^(-deltaG/(2.303*R*T))
+//Kc related to Ecell
+Kc2=10^((n*F*Ecell)/(2.303*R*T))
+printf('Thus (i)deltaG = %e',deltaG)
+printf('\n(ii)Kc in relation with deltaG = %e',Kc1)
+printf('\n(iii)Kc in relation with Ecell = %e',Kc2)