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Diffstat (limited to '3012/CH13/EX13.12/Ex13_12.sce')
-rwxr-xr-x | 3012/CH13/EX13.12/Ex13_12.sce | 34 |
1 files changed, 34 insertions, 0 deletions
diff --git a/3012/CH13/EX13.12/Ex13_12.sce b/3012/CH13/EX13.12/Ex13_12.sce new file mode 100755 index 000000000..7220df506 --- /dev/null +++ b/3012/CH13/EX13.12/Ex13_12.sce @@ -0,0 +1,34 @@ + +// Given:- +// Complete combustion of liquid octane with O2 is described by +// C8H18(l) + 12.5O2 ----- 8CO2 + 9H2O + +// Part(a) +Rbar = 8.314 // universal gas constant in SI units +Tnot = 298.15 // in kelvin +// From table A-25 +gbarC8H18 = 6610.0 +gbarO2 = 0 +gbarCO2 = -394380 +gbarH2O = -228590 +yO2 = 0.2035 +yCO2 = 0.0003 +yH2O = 0.0312 +M = 114.22 // molecular weight of liquid octane + +// Calculations +ech = ((gbarC8H18 + 12.5*gbarO2 -8*gbarCO2 -9*gbarH2O) + Rbar*Tnot*log(yO2**12.5/(yCO2**8*yH2O**9 )))/M +// Result +printf( ' Part(a) the chemical exergy obtained on a unit mass basis is: %.2f kJ/K',ech) + +// Part(b) +// With data from Table A-25 and Model II of Table A-26 +gbarH2O = -237180.0 +ebarCO2 = 19870.0 +ebarH2O = 900.0 +ebarO2 = 3970.0 + +// Calculation +ech = ((gbarC8H18 + 12.5*gbarO2 -8*gbarCO2 - 9*gbarH2O) + 8*ebarCO2 + 9*ebarH2O - 12.5*ebarO2)/M +// Result +printf( ' Part(b) chemical exergy on a unit mass basis is: %.3f kJ/K',ech) |