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+//developed in windows 8 operating system 64bit
+//platform Scilab 5.4.1
+//example 28_5w
+
+clc;clear;
+//Given Data
+
+area=100*10^-4;         //Area of the cross section (Unit:m^-2)
+thick_a=0.04;           //Thickness of part A (Unit: m)
+thick_b=0.025;          //Thickness of part B (Unit:m) 
+k_a=200;                //Thermal conductivity of A (Unit: W/m-degree centigrade)
+k_b=400;                //Thermal conductivity of B (Unit: W/m-degree centigrade)
+theta_a=100;            //Temperature at A (Unit:degree centigrade)
+theta_b=0;              //Temperature at B (Unit:degree centigrade)
+
+//calculation
+
+rate_heat_flow=area*(theta_a-theta_b)/(thick_a/k_a+thick_b/k_b);    //Calculation of The rate of heat flow through any cross section (Unit:Watt)
+
+temp=rate_heat_flow*thick_b/(area*k_b);                             //Calculation of The temperature at the interface  (Unit: degree centigrade)
+
+equivalent_k=(thick_a+thick_b)/(thick_a/k_a+thick_b/k_b);           //Calculation of The equivalent thermal conductivity of the compound plate  (Unit: W/m-degree centigrade)
+
+disp(rate_heat_flow,"The rate of heat flow through any cross section is (Unit:Watt)");
+disp(temp,"The temperature at the interface is (Unit: degree centigrade)");
+disp(equivalent_k,"The equivalent thermal conductivity of the compound plate is (Unit: W/m-degree centigrade)");