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+
+// Ex4_27
+clc;
+
+// Given:
+t=110;// in min
+a=10;//dpmg^-1
+// Solution:
+k=0.693/t;
+N=a/k;// atoms of F18
+mass=(N*18)/6.022*10^23;
+mass1=(N*18*10^20)/(6.022*10^23);// in 10^-20 grams
+printf("The no. of atoms produced is %f and its mass is %f*10^-20 grams",N,mass1)