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+
+// Ex4_12
+clc;
+
+// Given:
+Ma=4;//mass of alpha particle
+Mr1=222;// mass of
+Mr2=208;
+Ea1=4.863;
+Ea2=6.082;
+// Solution:
+
+Er1=(Ma/Mr1)*Ea1;
+Et1=Ea1+Er1;
+printf("For Ra emitting alpha")
+printf("\n\tEnergy of recoil is %f MeV",Er1)
+printf("\n\tTotal transition energy is %f MeV",Et1)
+Er2=(Ma/Mr2)*Ea2;
+Et2=Ea2+Er2;
+printf("\nFor Bi emitting alpha")
+printf("\n\tEnergy of recoil is %f MeV",Er2)
+printf("\n\tTotal transition energy is %f MeV",Et2)
+