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+clc,clear
+//example 1.7
+//To find values of all trigonometric functions for 60 degree
+
+//take an equilateral triangle of side 2 and divide it by half
+//all 3 angles of equilateral triangle are same as 60 degree
+//the bisector of angle is also the perepndicual bisector of oppsoite side
+// Thus, A=60 B=30 C=90 in new triangle as shown in figure
+
+AB = 2; c=AB;
+AC = AB/2; b=AC;
+a=sqrt(c^2-b^2)//pythagoras theorem
+
+//For angle A=60 degree
+opposite = a;
+adjacent = b;
+hypotenuse = c;
+sin_60 = opposite / hypotenuse;
+cos_60 = adjacent / hypotenuse;
+tan_60 = opposite / adjacent;
+csc_60 = hypotenuse/opposite;
+sec_60 = hypotenuse/adjacent;
+cot_60 = adjacent / opposite;
+printf('ANGLE = 60 degree')
+printf('\nsin(60)=  %.4f ; cos(60)= %.4f;   tan(60)= %.4f;\n',sin_60,cos_60,tan_60)
+printf('csc(60)=  %.4f ; sec(60)= %.4f;   cot(60)= %.4f;',csc_60,sec_60,cot_60)
+
+//For angle ABC=30 degree
+opposite = b;
+adjacent = a;
+hypotenuse = c;
+sin_30 = opposite / hypotenuse;
+cos_30 = adjacent / hypotenuse;
+tan_30 = opposite / adjacent;
+csc_30 = hypotenuse/opposite;
+sec_30 = hypotenuse/adjacent;
+cot_30 = adjacent / opposite;
+printf('\n\nANGLE = 30 degree')
+printf('\nsin(30)=  %.4f ; cos(30)= %.4f;   tan(30)= %.4f;\n',sin_30,cos_30,tan_30)
+printf('csc(30)=  %.4f ; sec(30)= %.4f;   cot(30)= %.4f;',csc_30,sec_30,cot_30)