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+//chapter 5
+//example 5.24
+//Calculate energy corresponding to the ground and first two excited states
+//page 113
+clear;
+clc;
+//given
+a=1E-10; // in m (width of the well)
+m=9.1E-31; // in Kg (mass of electron)
+h=6.626E-34; // in J-s (Planck'c constant)
+n1=1, n2=2, n3=3; //  ground and first two excited states
+e=1.6*1E-19; // in C (charge of electron)
+//calculate
+// Since  E_n=n^2*h^2/(8*m*a^2)   (Energy corresponding to nth quantum state)
+E1=n1^2*h^2/(8*m*a^2); // calculation of energy corresponding to the Ground state
+printf('\nThe energy corresponding to the ground state is \tE1=%1.3E J',E1);
+E1=E1/e; //changing unit from J to eV
+printf('\n\t\t\t\t\t\t\t  =%.2f eV',E1);
+E2=n2^2*h^2/(8*m*a^2); // calculation of energy corresponding to the 1st excited state
+printf('\nThe energy corresponding to the 1st excited state is \tE2=%1.3E J',E2);
+E2=E2/e; //changing unit from J to eV
+printf('\n\t\t\t\t\t\t\t  =%.2f eV',E2);
+E3=n3^2*h^2/(8*m*a^2); // calculation of energy corresponding to the 2nd excited state
+printf('\nThe energy corresponding to the 2nd excited state is \tE3=%1.3E J',E3);
+E3=E3/e; //changing unit from J to eV
+printf('\n\t\t\t\t\t\t\t  =%.2f eV',E3);
+// Note: There is slight variation in the answer due to round off