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+//chapter 5
+//example 5.23
+//Calculate energy corresponding to the 2nd and 4th quantum states
+//page 112
+clear;
+clc;
+//given
+a=2; // in Angstrom (length of the box)
+m=9.1E-31; // in Kg (mass of electron)
+h=6.626E-34; // in J-s (Planck'c constant)
+n2=2, n4=4; //  two quantum states
+e=1.6*1E-19; // in C (charge of electron)
+//calculate
+a=a*1E-10; // since a is in Angstrom 
+// Since  E_n=n^2*h^2/(8*m*a^2)   (Energy corresponding to nth quantum state)
+E2=n2^2*h^2/(8*m*a^2); // calculation of energy corresponding to the 2nd quantum state
+printf('\nThe energy corresponding to the 2nd quantum state is \tE2=%1.3E J',E2);
+E2=E2/e; //changing unit from J to eV
+printf('\n\t\t\t\t\t\t\t  =%1.4E eV',E2);
+E4=n4^2*h^2/(8*m*a^2); // calculation of energy corresponding to the 4nd quantum state
+printf('\nThe energy corresponding to the 4nd quantum state is \tE4=%1.3E J',E4);
+E4=E4/e; //changing unit from J to eV
+printf('\n\t\t\t\t\t\t\t  =%1.4E eV',E4);
+// Note: The answer in the book is wrong due to calculation mistake