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+//chapter 4
+//example 4.6
+//find wavelength and energy
+//page 77
+clear;
+clc;
+//given
+h=1,k=1,l=1; // miller indices
+a=5.63; // in Angstrom  (lattice constant)
+theta=27.5; // in degree (Glancing angle)
+n=1; //order
+H=6.625E-34; // in J-s (Plank's constant)
+c=3E8; // in m/s (velocity of light)
+e=1.6E-19;// charge of electron
+//calculate
+d=a/sqrt(h^2+k^2+l^2); // calculation for interplanar spacing
+printf('\nThe lattice spacing is\td=%.2f Angstrom',d); 
+// Since 2dsin(theta)=n(lambda)
+// therefore we have
+lambda=2*d*sind(theta)/n; // calculation for wavelength
+printf('\nThe wavelength is\t=%.f Angstrom',lambda);
+E=H*c/(lambda*1E-10); //calculation of Energy
+printf('\nThe energy of X-rays is E=%1.3E J',E);
+E=E/e; // changing unit from J to eV
+printf('\n\t\tE=%1.3E eV',E);
+// Note: c=3E8 m/s but in solution c=3E10 m/s has been used that's why answer is different