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+//chapter 4
+//example 4.2
+//Find glancing angle
+//page 75
+clear;
+clc;
+//given
+h=1,k=1,l=0; //miller indices
+a=0.26; // in nanometer (lattice constant)
+lambda=0.065; // in nanometer (wavelength)
+n=2; // order
+//calculate
+d=a/sqrt(h^2+k^2+l^2); // calculation of interlattice spacing
+// Since 2dsin(theta)=n(lambda)
+// therefore we have
+theta=asind(n*lambda/(2*d));
+printf('\nThe glancing angle is \t%.2f degree',theta);
+//Note: there is slight variation in the answer due to round off