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+//  chapter 10
+// example 10.3
+// calculate isotropic mass at 5.1K
+// page 313
+clear;
+clc;
+// given
+M1=199.5; // in amu (isotropic mass at 5K)
+T1=5; // in K (first critical temperature)
+T2=5.1; // in K (second critical temperature)
+//calculate
+// since Tc=C*(1/sqrt(M)
+// therefore T1*sqrt(M1)=T2*sqrt(M2)
+// therefore we have M2=(T1/T2)^2*M1
+M2=(T1/T2)^2*M1; //calculation of isotropic mass at 5.1K
+printf('\nThe isotropic mass at 5.1K is \t M2=%.3f a.m.u.',M2);
+