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+// Display mode
+mode(0);
+// Display warning for floating point exception
+ieee(1);
+clear;
+clc;
+disp("Engineering Thermodynamics by Onkar Singh Chapter 8 Example 10")
+disp("at inlet to HP turbine,h2=3287.1 KJ/kg,s2=6.6327 KJ/kg K")
+h2=3287.1;
+s2=6.6327;
+disp("By interpolation state 3 i.e. for isentropic expansion betweeen 2-3 lies at 328.98oc at 30 bar.h3=3049.48 KJ/kg")
+h3=3049.48;
+disp("actual enthapy at 3_a,h3_a=h2-0.80*(h2-h3)in KJ/kg")
+h3_a=h2-0.80*(h2-h3)
+disp("enthalpy at inlet to LP turbine,h4=3230.9 KJ/kg,s4=6.9212 KJ K")
+h4=3230.9;
+s4=6.9212;
+disp("for ideal expansion from 4-6,s4=s6.Let dryness fraction at state 6 be x6.")
+s6=s4;
+disp("s6=6.9212=sf at 0.075 bar+x6* sfg at 0.075 bar in KJ/kg K")
+disp("from steam tables,at 0.075 bar,sf=0.5764 KJ/kg K,sfg=7.6750 KJ/kg K")
+sf=0.5764;
+sfg=7.6750;
+disp("so x6=(s6-sf)/sfg")
+x6=(s6-sf)/sfg
+x6=0.827;//approx.
+disp("h6=hf at 0.075 bar+x6*hfg at 0.075 bar in KJ/kg K")
+disp("from steam tables,at 0.075 bar,hf=168.79 KJ/kg,hfg=2406.0 KJ/kg")
+hf=168.79;
+hfg=2406.0;
+h6=hf+x6*hfg
+disp("for actual expansion process in LP turbine.")
+disp("h6_a=h4-0.85*(h4-h6) in KJ/kg")
+h6_a=h4-0.85*(h4-h6)
+disp("Ideally,enthalpy at bleed point can be obtained by locating state 5 using s5=s4.The pressure at bleed point shall be saturation pressure corresponding to the 140oc i.e from steam tables.Let dryness fraction at state 5 be x5.")
+p5=3.61;
+s5=s4;
+disp("s5_a=6.9212=sf at 140oc+x5*sfg at 140oc")
+disp("from steam tables,at 140oc,sf=1.7391 KJ/kg K,sfg=5.1908 KJ/kg K")
+sf=1.7391;
+sfg=5.1908;
+disp("so x5=(s5-sf)/sfg")
+x5=(s5-sf)/sfg
+x5=0.99;//approx.
+disp("h5=hf at 140oc+x5*hfg at 140oc in KJ/kg")
+disp("from steam tables,at 140oc,hf=589.13 KJ/kg,hfg=2144.7 KJ/kg")
+hf=589.13;
+hfg=2144.7;
+h5=hf+x5*hfg
+disp("actual enthalpy,h5_a=h4-0.85*(h4-h5)in KJ/kg")
+h5_a=h4-0.85*(h4-h5)
+disp("enthalpy at exit of open feed water heater,h9=hf at 30 bar=1008.42 KJ/kg")
+h9=1008.42;
+disp("specific volume at inlet of CEP,v7=0.001008 m^3/kg")
+v7=0.001008;
+disp("enthalpy at inlet of CEP,h7=168.79 KJ/kg")
+h7=168.79;
+disp("for pumping process 7-8,h8=h7+v7*(3.61-0.075)*10^2 in KJ/kg")
+h8=h7+v7*(3.61-0.075)*10^2
+disp("Applying energy balance at open feed water heater.Let mass of bled steam be m kg per kg of steam generated.")
+disp("m*h5+(1-m)*h8=h9")
+disp("so m=(h9-h8)/(h5-h8) in kg /kg of steam generated")
+m=(h9-h8)/(h5-h8)
+disp("For process on feed pump,9-1,v9=vf at 140oc=0.00108 m^3/kg")
+v9=0.00108;
+disp("h1=h9+v9*(70-3.61)*10^2 in KJ/kg")
+h1=h9+v9*(70-3.61)*10^2
+disp("Net work per kg of steam generated,W_net=(h2-h3_a)+(h4-h5_a)+(1-m)*(h5_a-h6_a)-{(1-m)*(h8-h7)+(h1-h9)}in KJ/kg steam generated")
+W_net=(h2-h3_a)+(h4-h5_a)+(1-m)*(h5_a-h6_a)-{(1-m)*(h8-h7)+(h1-h9)}
+disp("heat added per kg of steam generated,q_add=(h2-h1)+(h4-h3_a)in KJ/kg of steam generated")
+q_add=(h2-h1)+(h4-h3_a)
+disp("Thermal efficiency,n=W_net/q_add")
+n=W_net/q_add
+disp("in percentage")
+n=n*100
+disp("so thermal efficiency=39.03%%")
+disp("NOTE=>In this question there is some calculation mistake while calculating W_net and q_add in book, which is corrected above and the answers may vary.")
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