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+// Display mode
+mode(0);
+// Display warning for floating point exception
+ieee(1);
+clear;
+clc;
+disp("Engineering Thermodynamics by Onkar Singh Chapter 4 Example 6")
+T1=(-15+273.15);//inside temperature in K
+T2=(35+273);//atmospheric temperature in K
+Q2=40;//refrigeration capacity of storage plant in tonnes
+disp("cold storage plant can be considered as refrigerator operating between given temperatures limits")
+disp("capacity of plant=heat to be extracted=Q2 in KW")
+disp("we know that,one ton of refrigeration as 3.52 KW ")
+disp("so Q2=Q2*3.52 in KW")
+Q2=Q2*3.52
+disp("carnot COP of plant(COP_carnot)=1/((T2/T1)-1)")
+COP_carnot=1/((T2/T1)-1)
+disp("performance is 1/4 of its carnot COP")
+disp("COP=COP_carnot/4")
+COP=COP_carnot/4
+disp("also actual COP=Q2/W")
+disp("W=Q2/COP in KW")
+W=Q2/COP
+disp("hence power required(W)in KW")
+W
+
+
+
+
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