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+// Display mode
+mode(0);
+// Display warning for floating point exception
+ieee(1);
+clear;
+clc;
+disp("Engineering Thermodynamics by Onkar Singh Chapter 3 Example 10")
+n=500;//total number of persons
+q=50;//heat requirement per person in kcal/hr
+h1=80;//enthalpy of hot water enter in pipe in kcal/kg
+h2=45;//enthalpy of hot water leaves the pipe in kcal/kg
+g=9.81;//acceleartion due to gravity in m/s^2
+deltaz=10;//difference in elevation of inlet and exit pipe in m
+disp("above problem can be solved using steady flow energy equations upon hot water flow")
+disp("Q+m1*(h1+C1^2/2+g*z1)=W+m2*(h2+C2^2/2+g*z2)")
+disp("here total heat to be supplied(Q)in kcal/hr")
+Q=n*q
+disp("so heat lost by water(-ve),Q=-25000 kcal/hr")
+Q=-25000//heat loss by water in kcal/hr
+disp("there shall be no work interaction and change in kinetic energy,so,steady flow energy equation shall be,")
+disp("Q+m*(h1+g*z1)=m*(h2+g*z2)")
+disp("so water circulation rate(m)in kg/hr")
+disp("so m=Q*10^3*4.18/(g*deltaz-(h1-h2)*10^3*4.18")
+m=Q*10^3*4.18/(g*deltaz-(h1-h2)*10^3*4.18)
+disp("water circulation rate(m)in kg/min")
+m=m/60