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+// Display mode
+mode(0);
+// Display warning for floating point exception
+ieee(1);
+clear;
+clc;
+disp("Engineering Thermodynamics by Onkar Singh Chapter 12 Example 5")
+T1=25;//room temperature in degree celcius
+T4=2;//winter outside temperature in degree celcius
+h1=10;//heat transfer coefficient on inner window surfaces in W/m^2 oc
+h4=30;//heat transfer coefficient on outer window surfaces in W/m^2 oc
+k=0.78;//thermal conductivity of glass in W/m^2 oc
+A=75*10^-2*100*10^-2;//area in m^2
+deltax=10*10^-3;//glass thickness in m
+disp("R1=thermal resistance for convection heat transfer between inside room (1)and inside surface of glass window(2)=1/(h1*A)")
+disp("R2=thermal resistance for conduction through glass between inside of glass window(2)to outside surface of glass window(3)=deltax/(k*A)")
+disp("R3=thermal resistance for convection heat transfer between outside surface of glass window(3)to outside atmosphere(4)=1/(h4*A)")
+disp("total thermal resistance,R_total=R1+R2+R3 in oc/W")
+R_total=1/(h1*A)+deltax/(k*A)+1/(h4*A)
+disp("so rate of heat transfer,Q=(T1-T4)/R_total in W")
+Q=(T1-T4)/R_total
+disp("heat transfer rate from inside of room to inside surface of glass window.")
+disp("Q=(T1-T2)/R1")
+disp("so T2=T1-Q*R1 in degree celcius")
+R1=(1/7.5);
+T2=T1-Q*R1
+disp("Thus,inside surface of glass window will be at temperature of 9.26 oc where as room inside temperature is 25 oc")