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+// Display mode
+mode(0);
+// Display warning for floating point exception
+ieee(1);
+clear;
+clc;
+disp("Engineering Thermodynamics by Onkar Singh Chapter 11 Example 2")
+Q=800;//refrigeration capacity in tons
+Q_latent=335;//latent heat for ice formation from water in KJ/kg
+T1=(-7+273);//temperature of reservoir 1 in K
+T2=(27+273);//temperature of reservoir 2 in K
+disp("refrigeration capacity or heat extraction rate(Q)in KJ/s")
+Q=Q*3.5
+disp("let the ice formation rate be m kg/s")
+disp("heat to be removed from per kg of water for its transformation into ice(Q1)in KJ/kg.")
+Q1=4.18*(27-0)+Q_latent
+disp("ice formation rate(m)in kg=refrigeration capacity/heat removed for getting per kg of ice")
+m=Q/Q1
+disp("COP of refrigerator,=T1/(T2-T1)=refrigeration capacity/work done")
+COP=T1/(T2-T1)
+disp("also COP=Q/W")
+disp("so W=Q/COP in KJ/s")
+W=Q/COP
+disp("HP required")
+W=W/0.7457
+disp("NOTE=>In book,this question is solved by taking T1=-5 degree celcius,but according to question T1=-7 degree celcius so this question is correctly solved above by considering T1=-7 degree celcius.")