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+// Display mode
+mode(0);
+// Display warning for floating point exception
+ieee(1);
+clear;
+clc;
+disp("Engineering Thermodynamics by Onkar Singh Chapter 10 Example 5")
+Pb_mep=6*10^5;//brake mean effective pressure in pa
+N=600;//engine rpm
+m=0.25;//specific fuel consumption in kg/KWh
+D=20*10^-2;//bore of cylinder in m
+L=30*10^-2;//stroke in m
+k=26;//air to fuel ratio
+C=43*10^3;//calorific value in KJ/kg
+R=0.287;//gas constant in KJ/kg K
+T=(27+273);//ambient temperature in K
+P=1*10^2;//ambient pressure in Kpa
+disp("brake thermal efficiency(n)=3600/(m*C)")
+n=3600/(m*C)
+disp("in percentage")
+n=n*100
+disp("brake power(BP)in KW")
+disp("BP=4*Pb_mep*L*A*N/60000")
+A=%pi*D^2/4;
+BP=4*Pb_mep*L*A*N/60000
+disp("brake specific fuel consumption,m=mf/BP")
+disp("so mf=m*BP in kg/hr")
+mf=m*BP
+disp("air consumption(ma)from given air fuel ratio=k*mf in kg/hr")
+ma=k*mf
+disp("ma in kg/min")
+ma=ma/60
+disp("using perfect gas equation,")
+disp("P*Va=ma*R*T")
+disp("sa Va=ma*R*T/P in m^3/min")
+Va=ma*R*T/P
+disp("swept volume(Vs)=%pi*D^2*L/4 in m^3")
+Vs=%pi*D^2*L/4
+disp("volumetric efficiency,n_vol=Va/(Vs*(N/2)*no. of cylinder)")
+n_vol=Va/(Vs*(N/2)*4)
+disp("in percentage")
+n_vol=n_vol*100
+disp("NOTE=>In this question,while calculating swept volume in book,values of D=0.30 m and L=0.4 m is taken which is wrong.Hence above solution is solve taking right values given in book which is D=0.20 m and L=0.3 m,so the volumetric efficiency vary accordingly.")
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