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+clc;clear;
+//Example 3.9
+
+//part a
+disp('Part a');
+
+//given values
+P=200;
+x=0.6;
+
+//from Table A-5
+T=120.21;
+uf=504.50;
+ufg=2024.6;
+
+//calcualtions
+u=uf+(x*ufg);
+disp(T,'temperature in Celcius ');
+disp(u,'internal energy in kJ/kg');
+disp('saturated liquid–vapor mixture at a pressure of 200 kPa');
+
+
+//part b
+disp('Part b');
+
+//given values
+T=125;
+u=1600;
+
+//from Table A–4
+uf=524.83;
+ug=2534.3;
+//ug>u>ufg so its aturated liquid–vapor mixture
+P=232.23;
+
+//calculation
+ufg=ug-uf;
+x=(u-uf)/ufg;
+disp(P,'Pressure in kPa');
+disp(x,'x is');
+disp('saturated liquid–vapor mixture at a temp of 125 of celcius');
+
+
+//part c
+disp('Part c');
+
+//given values
+P=1000;
+u=2950;
+
+//from Table A–6
+uf=761.39;
+ug=2582.8;
+//u>ug so its superheated steam
+T=395.2;
+
+//calculation
+disp(T,'temperature in Celcius');
+disp('superheated vapor at 1MPa ');
+
+//part d
+disp('Part d');
+
+//given values
+T=75;
+P=100;
+
+//from Table A–5
+Tsat=151.83;
+//T<Tsat so it is a compressed liquid
+//the given pressure is much lower than the lowest pressure value in the compressed liquid table i.e 5 MPa
+//assuming, the compressed liquid as saturated liquid at the given temperature
+
+//from Table A-4
+u=313.99;
+disp(u,'Internal energy in kJ/kg');
+disp('the compressed liquid condition');
+
+
+//Part e
+disp('Part e');
+
+//given values
+P=850;
+x=0;
+
+//x=0 therefore it is a saturateed liquid condition
+//from Table A-5
+T=172.94;
+u=731.00;
+disp(T,'temperature in Celcius');
+disp(u,'Internal energy in kJ/kg');
+disp('saturateed liquid condition')