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+clc;clear;
+//Example 3.7
+
+//given values
+P=0.5;
+h=2890;
+
+//from Table A–6
+//at P=0.5 MPa
+T1=200;
+h1=2855.8;
+T2=250;
+h2=2961.0;
+// we need linear interpolation 
+
+//calculatiom
+//by interpolation we cab say that
+//h=h1+(T-T1)/(T2-T1)*(h2-h1)
+//we have to find T
+T=(h-h1)/(h2-h1)*(T2-T1)+T1;
+disp(T,'temperature of water in celcius')