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+clc;clear;
+//Example 15.11
+
+//given values
+Tsurr=298;//in K
+
+//contansts used
+Ru=8.314;//in kJ/kmol K
+
+//calculations
+
+//part - a
+// CH4 + 3(O2 + 3.76N2) = CO2 + 2H2O + O2 + 11.28N2
+//The amount of water vapor that remains in the products is determined as in Example 15–3
+Nv=0.43;//moles of water vapour
+Nw=1.57;//moles of water in liquid
+//hf values
+//methane as m
+hfm=-74850;
+//carbondioxide as c
+hfc=-393520;
+//water vapour as v
+hfv=-241820;
+//water in liquid as w
+hfw=-285830;
+Qout=1*hfm-1*hfc-Nv*hfv-Nw*hfw;
+disp(Qout,'in kJ/kmol')
+
+//part - b
+//entropy calculations by using table A-26
+//Si = Ni*(si - Ruln yiPm
+//reactants
+Sm=1*(186.16-Ru*log(1*1));
+So=3*(205.04-Ru*log(0.21*1));
+Sn=11.28*(191.61-Ru*log(.79*1));
+Sreact=Sm+So+Sn;
+//products
+Nt=Nv+1+1+11.28;//total moles
+yw=1;
+yc=1/Nt;
+yv=Nv/Nt;
+yo=1/Nt;
+yn=11.28/Nt;
+Sw=Nw*(69.92-Ru*log(yw*1));
+Sc=1*(213.80-Ru*log(yc*1));
+Sv=Nv*(188.83-Ru*log(yv*1));
+So=1*(205.04-Ru*log(yo*1));
+Sn=11.28*(191.61-Ru*log(yn*1));
+Sprod=Sc+Sw+So+Sn+Sv;
+Sgen=Sprod-Sreact+Qout/Tsurr;
+Sgen=ceil(Sgen);
+disp(Sgen,'exergy destruction in kJ/kmol - K');
+Xdestroyed=Tsurr*Sgen/1000;//factor of 1000 for converting kJ to MJ
+Xdestroyed=floor(Xdestroyed);
+disp(Xdestroyed,'in MJ/kmol');
+//This process involves no actual work. Therefore, the reversible work and energy destroyed are identical
+Wrev=Xdestroyed;
+disp(Wrev,'the reversible work in MJ/kmol')