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+//example 3.3
+clc; funcprot(0);
+phi=25; //degrees
+Es=620; //kN/m^2
+Gamma=18;//kN/m^2
+Df=0.6;
+B=0.6;
+L=1.2;
+Fqc=0.347;
+Nq=10.66;
+Nc=20.72;
+Ngamma=10.88;
+mu=0.3;
+Fyd=1;
+c=48;//kN/m^2
+q=Gamma*(Df+B/2);
+Ir=Es/(2*(1+mu)*(c+q*tan(phi*%pi/180)));
+disp(Ir,"value of Ir");
+Fcc=Fqc-(1-Fqc)/(Nq*tan(phi*%pi/180));
+Fcs=1+Nq/Nc*B/L;
+Fqs=1+B/L*tan(phi*%pi/180);
+Fys=1-0.4*B/L;
+Fcd=1+0.4*Df/B;
+Fqd=1+2*tan(phi*%pi/180)*(1-sin(phi*%pi/180))^2*Df/B;
+q1=0.6*18;
+Fyc=Fqc;
+qu=c*Nc*Fcs*Fcd*Fcc+q1*Nq*Fqs*Fqd*Fqc+1/2*Gamma*Ngamma*Fys*Fyd*Fyc;
+disp(qu,"ultimate bearing capacity in kN/m^2");
+