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+// find torque applied and tatal twist angle
+clc
+//solution
+//given
+L=3500//mm//total length
+//l1+l2+l3=3500
+do=100//mm
+di=62.5//mm
+d2=100//mm
+d3=87.5//mm
+t=47.5//N/mm^2//shear stress
+C=82.5*10^3//N/mm^2
+//refer fig 5.3
+pi=3.14
+J1=(pi/32)*[do^4-di^4]
+J2=(pi/32)*[d2]^4
+J3=(pi/32)*[d3]^4//mm^4
+//we know q=(T*l)/(C*J)//twist angle
+//q1=q2
+//(T*l1)/(C*J1)=(T*l2)/(C*J2)
+//therefore l1/l2=(J1/J2)=0.847
+//q1=q3
+//therefore (l1/l3)=(J1/J3)=1.447
+//l1+l2+l3=L=3500
+//l1+l1/0.847+l1/1.447=3500
+//l1(1+(1/0.847)+(1/1.447))=3500
+l1=3500/{1+(1/0.847)+(1/1.447)}
+l2=l1/0.847
+l3=l1/1.447
+//T/J=t/r
+T=(pi/16)*t*[(do^4-di^4)/do]//torque//N-mm
+//q=q1+q2+q3//total angle of twist
+q=(T/C)*[{l1/J1}+{l2/J2}+{l3/J3}]
+printf("the torque applied is,%f N-mm\n",T)
+printf("the total angle of twist is,%f radians",q) \ No newline at end of file