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+//find the load
+clc
+//refer fig 5.13
+//solution
+//given
+f=140//N/mm^2
+Ri=25//mm
+Ro=50//mm
+bi=19//mm
+ti=3//mm
+t=3//mm
+h=25//mm
+A=(3*22)+(3*19)//mm^2
+Rn={ti*(bi-t)+t*h}/{[(bi-t)*log((Ri+t)/Ri)]+[t*log(Ro/Ri)]}//mm
+R=Ri+{[(0.5*h^2*t)+(0.5*ti^2*(bi-t))]/{(h*t)+(ti*(bi-t))}}//mm
+e=R-Rn//mm
+x=50+R//mm
+//M=W*x//N-mm
+yi=Rn-Ri//mm
+//f1=W/A=0.008*W//N/mm^2//direct tensile stress
+//fbi=(M*yi)/(A*e*Ri)=0.115*W//N/mm^2
+//f=f1+fbi
+//0.123*W=140
+W=140/0.123//N
+printf("the value of e is,%f mm\n",e)
+printf("the value of Rn is,%f mm\n",Rn)
+printf("the load acting is,%f N",W) \ No newline at end of file