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+//find
+clc
+//solution
+//given
+m=2.97//kg
+x=0.15//m
+y=0.1125//m
+r2=0.1//m
+r1=0.15//m
+N2=240//rpm
+t=420//N/mm^2
+G=84*1000//N/mm^2
+C=8
+//ref fig 23.16
+w2=2*%pi*N2/60//rad/s
+w1=w2+(7.5*w2/100)//rad/s
+//let Fc1 and Fc2 be centri fugal forces a w1 and w2
+//S1=2*Fc1*x/y
+S1=2*m*r1*w1^2*x/y//N
+S2=2*m*r2*w2^2*x/y//N
+dx=(r1-r2)*y/x*1000//mm
+K=(4*C-1)/(4*C-4)+(0.615/C)
+W=S1//max force
+printf("dia of sprig wire is,%f vmm\n",sqrt((K*8*W*C)/(t*%pi)))
+printf("dia is say 7.62 mm,taking standard conditions rfom table 23.2\n")
+d=7.62
+D=C*d
+W1=S1-S2
+printf("mean dia is,%f mm\n",D)
+printf("numbr of tunrs are,%f \n",dx*G*d/(8*W1*C^3))
+printf("numbr of turns are say 16\n")
+n=16
+nb=n+2
+dxmax=dx*W/(W1)
+fL=nb*d + dxmax + 0.15*dxmax
+printf("free length is ,%f mm\n",fL)
+printf("pitch of coil is,%f mm",fL/(nb-1)) \ No newline at end of file