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+//find...
+clc
+//solution
+//given
+P=50000//W
+N=150//rpm
+n=75
+ft=4*10^6//N/m^2
+rho=7200
+Tmean=(P*60)/(2*%pi*N)//N-m
+printf("mean torque acig is,%f N-m\n",Tmean)
+//ref fig 22.14
+q=4*%pi
+Wdpc=Tmean*q
+Wp=1.4*Wdpc//work done in power stroke....eq1
+//from dia
+//Wp1=(0.5*%pi)*Tmax...eq2
+Tmax=Wp/1.571//N-m
+printf("max torque is,%f N-m\n",Tmax)
+//BG=BF-FG
+BG=Tmax-Tmean//N-m
+BF=Tmax
+dE=Wp*(BG/BF)^2//N-m
+printf("dE is,%f N-m\n",dE)
+//let D be mean dia
+//let v be peripheral velo
+v=sqrt(ft/rho)//m/s
+D=(v*60)/(N*%pi)//m
+printf("the dia of wheel is,%f m\n",D)
+//let t be thickness and b be width of rim
+//b=4t
+//A=b*t=4*t^2
+//N1-N2=0.01*N
+Cs=0.01
+//dE=E*2*Cs
+E=dE/(2*Cs)//N-m
+Erim=(15/16)*E//N-m
+printf("Erim is,%f N-m\n",Erim)
+m=Erim*2/v^2//kg
+t=sqrt(m/271468)
+printf("the thickness and width si,%f m\n,%f m\n",t,4*t)