diff options
Diffstat (limited to '278/CH22/EX22.11/ex_22_11.sce')
-rwxr-xr-x | 278/CH22/EX22.11/ex_22_11.sce | 95 |
1 files changed, 47 insertions, 48 deletions
diff --git a/278/CH22/EX22.11/ex_22_11.sce b/278/CH22/EX22.11/ex_22_11.sce index 9d122ee1b..4734e5bf9 100755 --- a/278/CH22/EX22.11/ex_22_11.sce +++ b/278/CH22/EX22.11/ex_22_11.sce @@ -1,49 +1,48 @@ -//find...
-clc
-//solution
-//given
-P=185*1000//W
-N=100//rpm
-//dE=0.15*E
-D=2.4//m
-R=1.2//m
-//let m be mass
-E=(P*60)/N//N-m
-dE=0.15*E//N-m
-rho=7200
-Cs=0.02
-v=(%pi*D*N)/60//m/s
-m=dE/(v^2*Cs)//kg
-printf("mass is,%f kg\n",m)
-//let t be thickness and b be width of rim
-//b=2t
-//m=A*%pi*D*rho
-//A=b*t=2*t^2
-t=sqrt(m/108588)//mm
-printf("the thicknes and width is,%f m\n,%f m\n",t,2*t)
-//let d be dia of hub ,d1 be dia of shaft,l be length of hub
-Tmean=(P*60)/(2*%pi*N)//N-m
-Tmax1=2*Tmean*1000//N-mm
-//d1=(Tmax1*16/(%pi*tf))^(1/3)
-printf("dia od shaft is,%f mm\n",(Tmax1*16/(%pi*tf))^(1/3))
-printf("the dia of shaft is say 165mm\n")
-d1=165//mm
-d=2*d1//mm
-l=2*t//mm
-printf("the dia of hub and length of hub is,%f mm\n,%f m\n",d,l)
-//let a1 be major and b1 be minor axis
-//a1=2*b1
-n=6
-fb=14//N/mm^2
-M=Tmax1*(D*1000-d)/(D*n*1000)//N-mm
-printf("bending moment is,%f N-mm\n",M)
-//Z=(%pi/32)*b1*a1^2=0.05*a1^3
-//fb=M/Z
-a1=(M/(fb*0.05))^(1/3)//mm
-b1=0.5*a1
-tf=40
-printf("major and minor axis is,%f mm\n,%f mm\n",a1,b1)
-printf("corrsponding to shaft of dia 165 mm,width is 45 mm and thicknss of key is 25 mm\n")
-//let L be length of key
-L=Tmax1/(45*tf*d1/2)//mm
+clc +//solution +//given +P=185*1000//W +N=100//rpm +//dE=0.15*E +D=2.4//m +R=1.2//m +//let m be mass +E=(P*60)/N//N-m +dE=0.15*E//N-m +rho=7200 +Cs=0.02 +v=(%pi*D*N)/60//m/s +m=dE/(v^2*Cs)//kg +printf("mass is,%f kg\n",m) +//let t be thickness and b be width of rim +//b=2t +//m=A*%pi*D*rho +//A=b*t=2*t^2 +t=sqrt(m/108588)//mm +printf("the thicknes and width is,%f m\n,%f m\n",t,2*t) +//let d be dia of hub ,d1 be dia of shaft,l be length of hub +Tmean=(P*60)/(2*%pi*N)//N-m +Tmax1=2*Tmean*1000//N-mm +//d1=(Tmax1*16/(%pi*tf))^(1/3) +tf=40; +printf("dia od shaft is,%f mm\n",(Tmax1*16/(%pi*tf))^(1/3)) +printf("the dia of shaft is say 165mm\n") +d1=165//mm +d=2*d1//mm +l=2*t//mm +printf("the dia of hub and length of hub is,%f mm\n,%f m\n",d,l) +//let a1 be major and b1 be minor axis +//a1=2*b1 +n=6 +fb=14//N/mm^2 +M=Tmax1*(D*1000-d)/(D*n*1000)//N-mm +printf("bending moment is,%f N-mm\n",M) +//Z=(%pi/32)*b1*a1^2=0.05*a1^3 +//fb=M/Z +a1=(M/(fb*0.05))^(1/3)//mm +b1=0.5*a1 +printf("major and minor axis is,%f mm\n,%f mm\n",a1,b1) +printf("corrsponding to shaft of dia 165 mm,width is 45 mm and thicknss of key is 25 mm\n") +//let L be length of key +L=Tmax1/(45*tf*d1/2)//mm printf("length of key is,%f mm\n",L)
\ No newline at end of file |