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+//determine dia of the shaft
+clc
+//solution
+//given
+//ref fig 14.9
+W=200//N
+L=300//mm
+D=200//mm
+R=100//mm
+P=1000//W
+N=120//rpm
+u=0.3
+Km=1.5
+Kl=2
+T=79.6*1000
+t=35//N/mm^2
+//T=(T1-T2)*R
+//T1-T2=796.....eq 1
+//log(T1/T2)*2.3=u*%pi
+//T1/T2=2.57.....eq 2
+//from 1 and 2
+T1=1303//N
+T2=507//N
+Wt=T1+T2+W//N
+M=Wt*L//N-mm
+Te=sqrt((Km*M)^2 + (Kl*T)^2)//N-mm
+//Te=(%pi/16)*t*d^3
+d=(Te/6.87)^(1/3)//mm
+printf("the dia of shaft is,%f mm",d)
+