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+//find length of each parallel fillet weld
+clc
+//solution
+//given
+//ref fig 10.15
+b=75//mm//width
+t=12.5//mm//thickness
+ft=70//N/mm^2
+T=56//N/mm^2
+l1=b-t//mm
+s=12.5//mm
+//let l2 be length of each parallel fillet for static loading
+//P=A*ft
+P=b*t*ft//N//max load
+P1=0.707*s*l1*ft//N
+//P2=1.414*s*l2*T=990*l2//N
+//P=P1+P2
+l2=(P-P1)/990//mm
+printf("the value of length of static weld is,%f mm\n",l2+12.5)
+//length of parallel fillet for fatique loading
+ft1=ft/1.5//N/mm^2
+T1=T/2.7//N/mm^2
+P11=0.707*s*l1*ft1//N
+//P2=1.414*s*l2*T1=366*l22//N
+//P=P1+P2
+l22=(P-P11)/366//mm
+printf("the value of length of static weld is,%f mm\n",l22+12.5)