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+//find max shear stress
+clc
+//solution
+//given
+//ref fig 10.32 and 33
+s=6//mm
+P=20*10^3//N
+l=40//mm
+b=90//mm
+//let t throat thickness
+//let x is distance of Cg from left edge
+x=l^2/(2*l+b)//mm
+//J=t*[(b+2*l)^3/12-(l^2*(b+l)^2/(b*2*l))]
+J=0.707*s*[{(b+2*l)^3/12}-{(l^2*(b+l)^2)/(b+2*l)}]//mm^4
+printf("the value of J is,%f mm^4\n",J)
+Bg=40
+e=200-x//mm
+r1=Bg-x//mm
+Ab=(90/2)//mm
+r2=sqrt(Ab^2+Bg^2)//mm
+//cos(q)=r2/r1=0.5625
+a=0.5625
+A=2*0.707*s*l+(0.707*s*b)//mm^2
+t1=P/A//N/mm^2'
+t2=P*e*r2/J//N/mm^2
+T=sqrt(t1^2 + t2^2 + 2*t1*t2*a)//N/mm^2'
+printf( "the value of x is,%f mm\n",x)
+printf("the value of direct shear stress is,%f N/mm^2\n",t1)
+printf("the value of secondary shear stress is,%f N/mm^2\n",t2)
+printf("the max shera stress is,%f N/mm^2",T) \ No newline at end of file