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+//Transport Processes and Seperation Process Principles
+//Chapter 2
+//Example 2.6-1
+//Principles of Momentum Transfer and Overall Balances
+//given data
+//oil density=892 kg/m3 , volumetric flow rate= (1.388*10^-3) m3/s, schedule 40 pipes are being used
+//a) 
+A1=0.02330*0.0929;//cross sectional area in m2
+A3=0.01414*0.0929;//cross sectional area in m2
+rho=892;//oil density=892 kg/m3
+m1=(1.388/1000)*rho;//mass flow rate in kg/s in pipes 1 and 2
+m3=m1/2;//mas flow rate divides eqully in 3 pipes
+v1=m1/(rho*A1);//velocity at 1 pipe'
+v3=m3/(rho*A3);//
+G1=(v1)*rho;
+mprintf("a) the total mass flow rate in pipe 1 is %f kg/s",m1)
+mprintf(" b) the velocity in pipe 1 is %f m/s",v1)
+mprintf(" the velocity in pipe 3 is %f m/s",v3)
+mprintf(" c) the mass velocity in pipe 1 is %f kg/s m2",G1)
+//end