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Diffstat (limited to '2705/CH8/EX8.14')
-rwxr-xr-x | 2705/CH8/EX8.14/Ex8_14.sce | 40 |
1 files changed, 40 insertions, 0 deletions
diff --git a/2705/CH8/EX8.14/Ex8_14.sce b/2705/CH8/EX8.14/Ex8_14.sce new file mode 100755 index 000000000..a93839efd --- /dev/null +++ b/2705/CH8/EX8.14/Ex8_14.sce @@ -0,0 +1,40 @@ +clear;
+clc;
+disp('Example 8.14');
+
+// aim : To determine
+// (a) the mass of fuel used per cycle
+// (b) the actual mass of air taken in per cycle
+// (c) the volume of air taken in per cycle
+
+// given values
+W = 15;// work done, [kJ/s]
+N = 5;// speed, [rev/s]
+C = .84;// mass composition of carbon
+H = .16;// mass composition of hydrogen
+ea = 1;// percentage excess air supplied
+CV = 45000;// calorificvalue of fuel, [kJ/kg]
+n_the = .3;// thermal efficiency
+P = 100;// pressuer, [kN/m^2]
+T = 273+15;// temperature, [K]
+R = .29;// gas constant, [kJ/kg K]
+
+// solution
+// (a)
+E = W*2/N/n_the;// energy supplied, [kJ/cycle]
+mf = E/CV;// mass of fuell used, [kg]
+mprintf('\n (a) Mass of fuel used per cycle is = %f g\n',mf*10^3);
+
+// (b)
+// basis 1 kg fuel
+mO2 = C*8/3+8*H;// mass of O2 requirea, [kg]
+smO2 = mO2/.23;// stoichiometric mass of air, [kg]
+ma = smO2*(1+ea);// actual mass of air supplied, [kg]
+m = ma*mf;// mass of air supplied, [kg/cycle]
+mprintf('\n (b) The mass of air supplied per cycle is = %f kg\n',m);
+
+// (c)
+V = m*R*T/P;// volume of air, [m^3]
+mprintf('\n (c) The volume of air taken in per cycle is = %f m^3\n',V);
+
+// End
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