diff options
Diffstat (limited to '2705/CH5/EX5.15/Ex5_15.sce')
-rwxr-xr-x | 2705/CH5/EX5.15/Ex5_15.sce | 35 |
1 files changed, 35 insertions, 0 deletions
diff --git a/2705/CH5/EX5.15/Ex5_15.sce b/2705/CH5/EX5.15/Ex5_15.sce new file mode 100755 index 000000000..e5ae9aa6a --- /dev/null +++ b/2705/CH5/EX5.15/Ex5_15.sce @@ -0,0 +1,35 @@ +clear;
+clc;
+disp('Example 5.15');
+
+// aim : To determine
+// the heat transferred and polytropic specific heat capacity
+
+// Given values
+P1 = 1;// initial pressure, [MN/m^2]
+V1 = .003;// initial volume, [m^3]
+P2 = .1;// final pressure,[MN/m^2]
+cv = .718;// [kJ/kg*K]
+Gamma=1.4;// heat capacity ratio
+
+// solution
+// Given process is polytropic with
+n = 1.3;// polytropic index
+// hence
+V2 = V1*(P1/P2)^(1/n);// final volume,[m^3]
+W = (P1*V1-P2*V2)*10^3/(n-1);// work done,[kJ]
+// so
+Q = (Gamma-n)*W/(Gamma-1);// heat transferred,[kJ]
+
+mprintf('\n The heat received or rejected by the gas during this process is Q = %f kJ',Q);
+if(Q>0)
+ disp('since Q>0, so heat is received by the gas')
+else
+ disp('since Q<0, so heat is rejected by the gas')
+end
+
+// now
+cn = cv*(Gamma-n)/(n-1);// polytropic specific heat capacity,[kJ/kg K]
+mprintf('\n The polytropic specific heat capacity is cn = %f kJ/kg K\n',cn);
+
+// End
|