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+clear;
+clc;
+disp('Example 2.3');
+
+
+
+//  Given values
+Q = -150; // Heat transferred out of the system, [kJ/kg]
+del_u = -400; // Internal energy decreased ,[kJ/kg]
+
+//  solution
+//  using equation [3],the non flow energy equation
+//  Q=del_u+W
+W = Q-del_u; //  [kJ/kg]
+mprintf('\n The Work done is, W =  %f kJ/kg \n',W);
+
+if(W>0)
+      disp('Since W>0, so Work done by the engine per kilogram of working substance')
+else
+   disp('Since <0, so Work done on the engine per kilogram of working substance')
+end
+
+//  End