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+// Exa 6.4
+clc;
+clear;
+close;
+// Given data
+R1= 200;// in kohm
+R1=R1*10^3;// in ohm
+R2=R1;// in ohm
+C1= 200;// in pF
+C1= C1*10^-12;// in F
+C2=C1;// in F
+f= 1/(2*%pi*R1*C1);// in Hz
+disp(f*10^-3,"Frequency of oscilltions in kHz is : ")
+
+// Note: Calculation to find the value of f in the book is wrong, so answer in the book is wrong