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+// Exa 5.26
+clc;
+clear;
+close;
+// Given data
+Is= 100;// in µA
+Is= Is*10^-6;// in A
+If= 95;// in µA
+If= If*10^-6;// in A
+Io= 10;// in mA
+Io= Io*10^-3;// in A
+A= Io/(Is-If);// n A/A
+Bita= If/Io;// A/A
+disp(A,"Value of A in A/A is : ")
+disp(Bita,"Value of Bita in A/A is : ")
+
+// Note: In the book , to evaluating the value of Bita, they putted wrong value of If (95 at place of 90)