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+// Exa 3.24
+clc;
+clear;
+close;
+// Given data
+VBE_1= 0.7;// in V
+VBE_2= 0.5;// in V
+V_T= 0.025;// in V
+I_C1= 10;// in mV
+I_C1= I_C1*10^-3;// in A
+// I_C1= I_S*%e^(VBE_1/V_T) (i)
+// I_C2= I_S*%e^(VBE_2/V_T) (ii)
+// Devide equation (ii) by (i)
+I_C2= I_C1*%e^((VBE_2-VBE_1)/V_T);// in A
+disp(I_C2*10^6,"The value of I_C2 in µA is : ")