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+// Exa 2.8
+clc;
+clear;
+close;
+// Given data 
+KnWbyL= 1;// in mA/V^2
+KnWbyL=KnWbyL*10^-3;// in A/V^2
+Vt= 1;// in V
+V_DD= 10;// in V
+R_D= 6;// in kΩ
+R_D= R_D*10^3;// in Ω
+R_S= 6;// in kΩ
+R_S= R_S*10^3;// in Ω
+R_G1= 10;// in MΩ
+R_G1= R_G1*10^6;// in Ω
+R_G2= 10;// in MΩ
+R_G2= R_G2*10^6;// in Ω
+V_G= V_DD*R_G2/(R_G1+R_G2);// in V
+// V_S= R_S*I_D
+// V_GS= V_G-V_S= V_G-R_S*I_D
+// Formula I_D= K'nW/2*L*(V_GS-Vt)^2, Putting the value of V_GS, We get
+// 18*I_D^2 -25*I_D +8= 0
+// I_D= 0.89 mA or I_D= 0.5
+I_D= 0.5;// in mA
+I_D=I_D*10^-3;// in A
+V_S= R_S*I_D;// in V
+V_GS= V_G-V_S;// in V
+V_D= V_DD-I_D*R_D;// in V
+disp(I_D*10^3,"The value of I_D in mA is : ")
+disp(V_S,"The value of V_S in volt is : ")
+disp(V_GS,"The value of V_GS in volt is : ")
+disp(V_D,"The value of V_D in volt is : ")
+disp("Since V_D > V_G - Vt , the transistor is operating in saturation , as initially assumed")
+
+