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+// Exa 2.22
+clc;
+clear; 
+close;
+// Given data 
+Vt= 0.9;// in V
+V_A= 50;// in V
+V_D= 2;// in V
+R_L= 10;// in MΩ
+R_L= R_L*10^3;// in Ω
+R_G= 10;// in MΩ
+R_G= R_G*10^6;// in Ω
+I_D= 500;// in µA
+I_D= I_D*10^-6;// in A
+V_GS= V_D;// in V
+ro= V_A/I_D;// in Ω
+gm= 2*I_D/(V_GS-Vt);// in A/V
+// vo= -gm*vi*(ro || R_L)
+vo_by_vi = -gm*(ro*R_L/(ro+R_L));// in V/V
+disp(vo_by_vi ,"The voltage gain in V/V is : ")
+// For I= 1 mA or twice the current 
+I_D1= I_D;// in A
+I_D2= 2*I_D1;// in A
+gm1= gm;// in A/V
+// Effect on V_D
+// I_D1/I_D2 = (V_GS1-Vt)^2/(V_GS2-Vt)^2
+V_GS1= V_GS;
+V_GS2= Vt+sqrt(2)*(V_GS1-Vt);// in V
+disp(V_GS2,"The new value of V_GS in volts is : ")
+// Effect on gm
+// gm1/gm2= sqrt(I_D1/I_D2)
+gm2= sqrt(I_D2/I_D1)*gm1;// in A/V
+disp(gm2*10^3,"The new value of gm2 in mA/V is : ")
+// Effect on ro
+// ro1/ro2= I_D2/I_D1
+ro1= ro;// in Ω
+ro2= I_D1*ro1/I_D2;// in Ω
+disp(ro2*10^-3,"The new value of ro in kΩ/V is : ")
+// Effect on gain
+// Av= -gm*(ro2 || R_L)
+Av= -gm*(ro2*R_L/(ro2+R_L));// in V/V
+disp(Av,"The new value of voltage gain in V/V is : ")
+
+// Note: There is some difference between  the new value of voltage gain in book and coding. The reason behind this is that , 
+// the accurate value of new value of gm is 1.2856487 and in the book 1.3 has  taken at place of 1.2856487. 
+// If we take this value of new value of gm 1.3 at place of 1.2856487 then our new voltage gain value will be same as in the book
+
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