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+// Exa 2.20
+clc;
+clear; 
+close;
+// Given data 
+unCox= 20*10^-6;//in A/V^2
+upCox= unCox/2.5;// in A/V^2
+V_DD= 3;//in V
+Vt= 1;// in V
+W= 30;// in µm
+L= 10;// in µm
+
+
+// V_GS1= V_GS2
+// Formula V_DD= V_GS1+V_GS2
+V_GS1= V_DD/2;//in V
+V_GS2= V_GS1;// in V
+V2= V_GS1;// inV
+I1= 1/2*unCox*W/L*(V_GS1-Vt)^2;// in A
+// Both transistor have V_D = V_G and therefore they are operating in saturation 
+//1/2*unCox*W/L*(V4-Vt)^2 = 1/2*upCox*W/L*(V_DD-V4-Vt)
+V4= (V_DD-Vt+sqrt(unCox/upCox))/(1+sqrt(unCox/upCox));
+I3= 1/2*unCox*W/L*(1.39-Vt)^2 
+disp(V2,"The value of V2 in volt is : ")
+disp(I1*10^6,"The value of I1 in µAis : ")
+disp(V4,"The value of V4 in volt is : ")
+disp(I3*10^6,"The value of I3 in µAis : ")