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+//Ex_7_11
+clc;
+clear;
+close;
+format('v',6);
+//given data :
+VBE=0.7;////V
+Beta=100;///Current Gain
+//Part (a)
+VCC=6;////V
+VEE=0;////V
+VB=2;////V
+RE=18;//kohm
+RC=3;//kohm
+VE=VB-VBE;//V
+disp(VE,"(a) Emitter Voltage(V) : ");
+IE=1;///mA
+IC=IE*Beta/(1+Beta);///mA
+VC=VCC-IC*RC;//V
+if VC>VE then
+    disp("Circuit is in active mode.");
+end;
+//Part (b)
+VEE=6;////V
+VCC=0;////V
+VB=1;////V
+RE=10;//kohm
+RC=10;//kohm
+VE=VB+VBE;//V
+disp(VE,"(b) Emitter Voltage(V) : ");
+IE=(VEE-VE)/RE;///mA
+IC=IE;///mA(Assumed nearly equal)
+VC=VCC+IC*RC;//V
+if VC>VB then
+    disp("Circuit is in saturation mode.");
+end;
+//Part (c)
+VEE=9.5;////V
+VCC=-50;////V
+VB=-5;////V
+RE=200;//kohm
+RC=20;//kohm
+VE=VB+VBE;//V
+disp(VE,"(c) Emitter Voltage(V) : ");
+IE=(VEE-VE)/RE;///mA;///mA
+IC=IE*Beta/(1+Beta);///mA
+VC=VCC-IC*RC;//V
+if VC>VE then
+    disp("Circuit is in active mode.");
+elseif VC<VE
+    disp("Circuit is in reverse active mode.")
+end;
+//Part (d)
+VEE=-30;////V
+VCC=-10;////V
+VB=-20;////V
+RE=6;//kohm
+RC=2;//kohm
+VE=VB-VBE;//V
+disp(VE,"(d) Emitter Voltage(V) : ");
+IE=(VEE-VE)/RE;///mA;///mA
+IC=IE*Beta/(1+Beta);///mA
+VC=VCC-IC*RC;//V
+if VC>VE then
+    disp("Circuit is in active mode.");
+end;
+//Note : Printing error in part (a) in the textbook. Answer is also not accurate in the textbook for part(c)