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+//Example 5_36
+clc;
+clear;
+close;
+format('v',5);
+//given data :
+Eta=1;//for Ge
+T=300;//K
+VT=0.026;//V(Thermal Voltage)
+VF=5;///V
+//I=I0;///given
+IByI0=1;//ratio
+//Using I=I0*(exp(V/VT)-1)
+V=log(IByI0+1)*VT;//V
+V2=VF-V;//V(Voltage across 2nd diode)
+disp(V2,"(a) Voltage across each junction(V) : ");
+//Part (b)
+format('v',6);
+Vz=4.9;//V
+Vrb=Vz;//V(Across reverse biased diode)
+V2=VF-Vrb;//V
+I0=6;//micro A
+I=I0*(exp(V2/VT)-1);//micro A
+disp(I,"(b) Current in the circuit(micro A) : ");
+//Note : Answer in the textbook is not accurate.