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+//Example 1_30
+clc;
+clear;
+close;
+format('v',5);
+//given data :
+I1=10;//A
+V2=12;//V
+R1=2;//ohm
+R2=2;//ohm
+R3=6;//ohm
+R4=6;//ohm
+//solution by Norton Theorem
+RL=R4;//ohm
+//Short Circuit AB
+ISC1=I1*R1/(R1+R2);//A//by current source
+ISC2=V2/R3;//A///by voltage source
+ISC=ISC1+ISC2;//A
+Req=(R1+R2)*R3/(R1+R2+R3);//ohm
+//Norton equivalent current
+I=ISC*Req/(Req+RL);//A
+disp(I,"By Nortons theorem, Current through 6 ohm resistance connected across AB(A)");
+//solution by Thevenin Theorem
+Rth=Req;//ohm
+//Converting current source into Voltage source
+V1=I1*R1;//V//Converted source
+//Applying KVL
+I=poly(0,'I');//A
+eqn=V1-R1*I-R2*I-R3*I-V2;//
+I=roots(eqn);//A
+VOC=V2+R3*I;//A
+I=VOC/(Rth+RL);//A
+disp(I,"By Thevenins theorem, Current through 6 ohm resistance connected across AB(A)");
+//Unit of current is given wrong in the book.