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+// FUNDAMENTALS OF ELECTICAL MACHINES 
+// M.A.SALAM 
+// NAROSA PUBLISHING HOUSE 
+// SECOND EDITION
+
+// Chapter 6 : CONTROL AND STARTING OF A DC MOTORS
+// Example : 6.5
+
+clc;clear; // clears the console and command history 
+
+// Given data
+V_t = 230         // shunt motor supply voltage in V
+R_a = 0.4         // armature resistance in ohm
+I_a = 30          // armature current in A
+n = 3             // number of steps
+
+// caclulations 
+R_1 = V_t/I_a        // maximum value of current in ohm
+k = (R_1/R_a)^(1/3)  // constant
+R_2 = R_1/k          // other value of resistance in ohm
+R_3 = R_2/k          // other value of resistance in ohm
+R_4 = R_3/k          // other value of resistance in ohm
+R_1step = R_1-R_2    // resistance of the 1st step in ohm
+R_2step = R_2-R_3    // resistance of the 1st step in ohm
+R_3step = R_3-R_4    // resistance of the 1st step in ohm
+
+// display the result 
+disp("Example 6.5 solution");
+printf(" \n resistance of the 1st step in ohm \n R_1step = %.1f ohm \n", R_1step);
+printf(" \n resistance of the 2nd step in ohm \n R_2step = %.1f ohm \n", R_2step);
+printf(" \n resistance of the 3rd step in ohm \n R_3step = %.2f ohm \n", R_3step);