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+// FUNDAMENTALS OF ELECTICAL MACHINES 
+// M.A.SALAM 
+// NAROSA PUBLISHING HOUSE 
+// SECOND EDITION
+
+// Chapter 6 : CONTROL AND STARTING OF A DC MOTORS
+// Example : 6.4
+
+clc;clear; // clears the console and command history 
+
+// Given data
+N = 1100         // speed of dc series motor in rpm
+P = 4            // number of poles
+I_a1 = 15        // supply current to dc series motor in A
+V_t = 220        // supply voltage in V
+R_a = 0.9        // series armature resistance in ohm
+R_se1 = 0.6      // series field resistance in ohm
+I_a2 = 25        // supply current to dc series motor in A
+// phi2 = 0.8*phi1 
+// phi1/phi2 = 1.25
+
+// caclulations 
+E_b1 = V_t-I_a1*(R_a+R_se1)    // back emf in V
+R_se2 = 0.6/4                 // value of resistance per path in ohm
+E_b2 = V_t-I_a2*(R_a+R_se2)   // back emf in V
+N_2 = (E_b2/E_b1)*1.25*N      // new speed in rpm 
+
+// display the result 
+disp("Example 6.4 solution");
+printf(" \n New speed \n N_2 = %.1f rpm \n", N_2);
+