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+// FUNDAMENTALS OF ELECTICAL MACHINES 
+// M.A.SALAM 
+// NAROSA PUBLISHING HOUSE 
+// SECOND EDITION
+
+// Chapter 5 : DIRECT CURRENT MOTORS 
+// Example : 5.4 
+
+clc;clear; // clears the console and command history 
+// Given data 
+I = 40;      // current in A 
+V_t = 230;   // supply in V
+N = 1100;    // speed in rpm
+R_a = 0.25;  // armature resistance in Ω
+R_sh = 230;  //shunt resistance in Ω 
+
+
+// caclulations 
+I_sh = V_t/R_sh;       // shunt field current in A
+I_a = I - 1;           // armature current in A
+E_b = V_t - I_a*R_a;   // back emf 
+T_a = 9.55*E_b*I_a/N;  //  amrature torque in N-m
+ 
+ // display the result 
+disp("Example 5.4 solution");
+printf("\n The armature torque is \n T_a = %.2f N-m ",T_a );