4 files changed, 121 insertions, 0 deletions
diff --git a/2642/CH10/EX10.1/Ex10_1.sce b/2642/CH10/EX10.1/Ex10_1.sce
new file mode 100755
index 000000000..f10336aec
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+++ b/2642/CH10/EX10.1/Ex10_1.sce
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+// FUNDAMENTALS OF ELECTICAL MACHINES 
+// M.A.SALAM 
+// NAROSA PUBLISHING HOUSE 
+// SECOND EDITION
+
+// Chapter 10 : SYNCHRONOUS MOTOR
+// Example : 10.1
+
+clc;clear; // clears the console and command history 
+
+// Given data
+V = 2.5*10^3 // supply voltage in V
+R_r = 0.12   // per phase resistance in ohm
+X_r = 3.2    // syncronous reactance in ohm
+I_a = 185    // line current in A
+pf = 0.8     // leading power factor
+
+// caclulations
+phi = acosd(pf)
+V_t = V/sqrt(3)    // terminal voltage per phase in V
+Z_s = R_r+%i*X_r   // impedance per phase ohm
+beta = atand(X_r/R_r)
+E_r = I_a*Z_s      // resultant voltage due to impedance in V
+E_f = sqrt(V_t^2+abs(E_r)^2-2*V_t*abs(E_r)*cosd(beta+phi)) // excitation voltage per phase in V
+
+
+// display the result  
+disp("Example 10.1 solution"); 
+printf(" \n Excitation voltage per phase \n E_f = %.2f V \n", E_f );
+
diff --git a/2642/CH10/EX10.2/Ex10_2.sce b/2642/CH10/EX10.2/Ex10_2.sce
new file mode 100755
index 000000000..e9344ff4f
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+++ b/2642/CH10/EX10.2/Ex10_2.sce
@@ -0,0 +1,33 @@
+// FUNDAMENTALS OF ELECTICAL MACHINES 
+// M.A.SALAM 
+// NAROSA PUBLISHING HOUSE 
+// SECOND EDITION
+
+// Chapter 10 : SYNCHRONOUS MOTOR
+// Example : 10.2
+
+clc;clear; // clears the console and command history 
+
+// Given data
+kVA = 1200   // kVA ratings
+V = 14*10^3  // supply voltage in V
+R_r = 4.8    // per phase resistance in ohm
+X_r = 35     // syncronous reactance in ohm
+pf = 0.95    // leading power factor
+
+// caclulations
+phi = acosd(pf)
+Z_s = R_r+%i*X_r           // impedance per phase ohm
+I_a = kVA*10^3/(sqrt(3)*V) // armature current in A
+E_r = I_a*Z_s              // resultant voltage due to impedance in V
+V_t = V/sqrt(3)            // terminal voltage per phase in V
+b = atand(X_r/R_r)         // beta value
+E_f = sqrt(V_t^2+abs(E_r)^2-2*V_t*abs(E_r)*cosd(b-phi)) // excitation voltage per phase in V
+teta = sind(64)
+D = (E_r*teta/E_f)         // torque angle
+delta = asind(abs(D))
+
+// display the result  
+disp("Example 10.2 solution"); 
+printf(" \n Excitation voltage per phase \n E_f = %.2f V \n", E_f );
+printf(" \n Torque angle at 0.95 power factor lagging \n delta = %.2f degree \n", delta );
diff --git a/2642/CH10/EX10.3/Ex10_3.sce b/2642/CH10/EX10.3/Ex10_3.sce
new file mode 100755
index 000000000..5af584787
--- /dev/null
+++ b/2642/CH10/EX10.3/Ex10_3.sce
@@ -0,0 +1,32 @@
+// FUNDAMENTALS OF ELECTICAL MACHINES 
+// M.A.SALAM 
+// NAROSA PUBLISHING HOUSE 
+// SECOND EDITION
+
+// Chapter 10 : SYNCHRONOUS MOTOR
+// Example : 10.3
+
+clc;clear; // clears the console and command history 
+
+// Given data
+V = 440          // supply voltage in V
+R_a = 1.5        // per phase resistance in ohm
+X_a = 8          // syncronous reactance in ohm
+P = 4            // number of poles
+f = 50           // supply frequency in Hz
+pf = 0.9         // leading power factor
+I_a = 50         // armature current in A
+
+// caclulations
+V_t = V/sqrt(3)      // terminal voltage per phase in V
+phi = acosd(pf)      // angle in degree
+Z_s = R_a+%i*X_a     // impedance per phase ohm
+E_r = I_a*abs(Z_s)        // resultant voltage due to impedance in V
+bet = atand(X_a/R_a)
+E_f = sqrt(V_t^2+E_r^2-2*V_t*E_r*cosd(bet+phi)) // excitation voltage per phase in V
+P_dm = (((E_f*V_t)/Z_s)-((E_f^2*R_a)/Z_s^2))          // maximum power per phase in W
+
+// display the result  
+disp("Example 10.3 solution"); 
+printf(" \n Maximum power per phase \n P_dm = %.2f W \n", P_dm );
+printf(" \n In textbook solution they took E_f = 513.5V instead of 533.33V");
diff --git a/2642/CH10/EX10.4/Ex10_4.sce b/2642/CH10/EX10.4/Ex10_4.sce
new file mode 100755
index 000000000..fd29f7240
--- /dev/null
+++ b/2642/CH10/EX10.4/Ex10_4.sce
@@ -0,0 +1,26 @@
+// FUNDAMENTALS OF ELECTICAL MACHINES 
+// M.A.SALAM 
+// NAROSA PUBLISHING HOUSE 
+// SECOND EDITION
+
+// Chapter 10 : SYNCHRONOUS MOTOR
+// Example : 10.4
+
+clc;clear; // clears the console and command history 
+
+// Given data
+P = 4 // number of poles
+f = 50 // supply frequency in Hz
+V_t = 1500 // terminal voltage per phase in V
+E_f = 1000 // excitation voltage per phase in V
+Z_s = 12 // synchronnous impedance in ohm
+R_a = 1.5 //armature resistance in ohm
+
+// caclulations
+P_dm = (((E_f*V_t)/Z_s)-((E_f^2*R_a)/Z_s^2)) // maximum power per phase in W
+T_dm = 9.55*P_dm/1500 // maximum torque in N-m
+
+// display the result  
+disp("Example 10.4 solution"); 
+printf(" \n Maximum power developed \n P_dm = %.0f W \n", P_dm );
+printf(" \n Maximum toruqe \n T_dm = %.1f N-m \n", T_dm );