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diff --git a/260/CH7/EX7.5/7_5.sce b/260/CH7/EX7.5/7_5.sce
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+++ b/260/CH7/EX7.5/7_5.sce
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+//Eg-7.5
+//pg-338
+
+clear
+clc
+
+x = [0 1 2 3 4];
+y = [1 2 9 22 41];
+
+m = length(x);
+n = 2;    //since we have 2 variables
+
+//Using S for summation    eg: Sx2y => summation(x^2*y)
+
+Sx = sum(x);
+
+Sx2 = sum(x.^2);
+
+Sx3 = sum(x.^3);
+
+Sx4 = sum(x.^4);
+
+Sy = sum(y);
+
+Sxy = sum(x.*y);
+
+Sx2y = sum((x.^2).*y);
+
+a(1,1) = Sx2 - (Sx)^2/m;
+a(1,2) = Sx3 - Sx*Sx2/m;
+a(2,1) = Sx3 - Sx2*Sx/m;
+a(2,2) = Sx4 - Sx2^2/m;
+
+c(1,1) = Sxy - Sx*Sy/m;
+c(2,1) = Sx2y - Sx2*Sy/m;
+
+printf('\nA =')
+disp(a)
+printf('c =')
+disp(c)
+
+b = inv(a)*c;
+
+printf('Solving the matrix equation  Ab = c using matrix inversion gives\n\nb=')
+disp(b)
+
+//The coefficient 'alpha' can be obtained from equaiton 'alpha' = Sy/m - (b(1)*Sx + b(2)*Sx2)/m ;
+
+alpha = Sy/m - (b(1)*Sx + b(2)*Sx2)/m ;
+
+printf('\nThe coefficent alpha = %f\n',alpha)
+
+printf('\nThe lease square polynomial of second order is, thus \n    y = %f + (%f)*x + (%f)*x^2\n\n',alpha,b(1),b(2))