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diff --git a/257/CH11/EX11.10/example_11_10.sce b/257/CH11/EX11.10/example_11_10.sce
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+//there is a pole at the origin and contribution of gain k
+
+k=10^(14/20)          //20*log(k)=14
+
+disp("equation of starting line is y=-20*log(w)+14")
+wc1=10^(0)
+disp(wc1,"hence at wc1, 14=-20*log(wc1)+14. that is wc1 = ")
+y1=poly([1 1/wc1],'s','coeff')
+
+disp("equation of next line is y=-40*log(w)+14")
+wc2=10^(40/40)            //-40*log(wc2)=-40
+disp(wc2,"wc2=")
+y2=poly([1 1/wc2],'s','coeff')
+
+wc3=50              //given
+y3=poly([1 1/wc3],'s','coeff')
+
+TF= k*(y2)/((y1)*(y3))
+disp(TF,"transfer function = ")