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+//Ex8_7
+clc
+RL = 1.2*10^3
+//assuming Rs = RL as given in problem
+Rs = RL
+//assuming values for h-parameters
+hie = 1.0*10^3
+hre=2.5*10^-4
+hfe = 50
+hoe = 25*10^-6
+disp("RL = "+string(RL)+"ohm")//load resistance
+disp("Rs = RL = "+string(RL)+"ohm")//source resistance
+//h-parameters for CE transistor amplifier are as follows:
+disp("hie = "+string(hie)+"ohm")//input resistance of CE transistor
+disp("hre = "+string(hre))//voltage gain of CE transistor
+disp("hfe = "+string(hfe))//current gain of CE transistor
+disp("hoe = "+string(hoe)+"mho")//output conductance of CE transistor
+//calculation for current gain:
+Ai=-hfe/(1+(hoe*RL))
+disp("Ai = -hfe/(1+(hoe*RL)) = "+string(Ai))
+//calculation for input impedence:
+Ri = hie+(hre*Ai*RL)
+disp("Ri = hie+(hre*Ai*RL) = "+string(Ri)+"ohm")
+//calculation for voltage gain:
+disp("Av = Ai*RL/Ri")
+Av = Ai*RL/Ri
+disp("   = "+string(Av))
+//calculation for output impedence:
+Ro = 1/((hoe - (hfe*hre)/(hie+Rs)))
+disp("Ro = 1/((hoe - (hfe*hre)/(hie+Rs)))")
+disp("     = "+string(Ro)+"ohm")
+//current gain with source impedence:
+Ais=(Ai*Rs)/(Ri+Rs)
+disp("Ais = (Ai*Rs)/(Ri+Rs)= "+string(Ais))
+//voltage gain with source impedence:
+Avs = Av*Ri/(Ri+Rs)
+disp("Avs = Av*Ri/(Ri+Rs) = "+string(Avs))
+
+
+
+// NOTE : calculation in the textbook for the above problem is wrong.
+//        while calculating Ri author has use "hie = 1.2*10^3" instead of ASSUMED9 value i.e., "hie = 1.0*10^3"