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+// Chapter8
+// Design  a contineously adjusted supply b/w 2V to 5 V
+// Page.No-279
+// Example8_5
+//Figure 8.15.1
+// Given
+clear;clc;
+Vref=7.15;            //in V
+Vout=5;            //in V
+//(R1b+R2)/R2=Vref/Vout;
+printf("\n For maximum case (R1b+R2)/R2 is = %.2f \n",Vref/Vout); // Result
+R2=1;              // In Ohm (Assumption)
+R1b=Vref/Vout-1;
+printf("\n For R2=1 Ohm R1b:R2 is = %.2f:%.0f \n",R1b,R2); // Result
+Voutm=2;           // in V
+printf("\n For maximum case (R1a+R1b+R2)/R2 is = %.3f \n",Vref/Voutm); // Result
+R1a=Vref/Voutm-1-0.43;
+printf("\n For R2=1 Ohm R1b:R2 is = %.3f:%.0f \n",R1a,R2); // Result
+R1a=10000;          //in Ohm        (Assumption)
+R2=R1a/2.145;
+printf("\n Value of R2 is = %.f Ohm\n",R2); // Result
+//Similarly
+R1b=R2*0.43;
+printf("\n Value of R1b is = %.f Ohm\n",R1b); // Result
+//Ilimit=Vsense/rsc;
+Vsense=0.65;            //in V
+Ilimit=1;           //in Amp
+Rsc=Vsense/Ilimit;
+printf("\n Value of current sense resistor is = %.f Ohm\n",Rsc); // Result
+R1=6000;                //in Ohm
+R3=R1*R2/(R1+R2);
+printf("\n Value of minimum drift resistor is = %.f Ohm\n",R3); // Result
+Ic=1;               //in Amp
+Ib=0.150;           //in Amp
+B=Ic/Ib;
+printf("\n Value of B minimum  = %.2f \n",B); // Result
+